Integrand size = 18, antiderivative size = 109 \[ \int \sqrt {d x} (a+b \arccos (c x))^2 \, dx=\frac {2 (d x)^{3/2} (a+b \arccos (c x))^2}{3 d}+\frac {8 b c (d x)^{5/2} (a+b \arccos (c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{4},\frac {9}{4},c^2 x^2\right )}{15 d^2}+\frac {16 b^2 c^2 (d x)^{7/2} \, _3F_2\left (1,\frac {7}{4},\frac {7}{4};\frac {9}{4},\frac {11}{4};c^2 x^2\right )}{105 d^3} \]
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Time = 0.09 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {4724, 4806} \[ \int \sqrt {d x} (a+b \arccos (c x))^2 \, dx=\frac {16 b^2 c^2 (d x)^{7/2} \, _3F_2\left (1,\frac {7}{4},\frac {7}{4};\frac {9}{4},\frac {11}{4};c^2 x^2\right )}{105 d^3}+\frac {8 b c (d x)^{5/2} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{4},\frac {9}{4},c^2 x^2\right ) (a+b \arccos (c x))}{15 d^2}+\frac {2 (d x)^{3/2} (a+b \arccos (c x))^2}{3 d} \]
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Rule 4724
Rule 4806
Rubi steps \begin{align*} \text {integral}& = \frac {2 (d x)^{3/2} (a+b \arccos (c x))^2}{3 d}+\frac {(4 b c) \int \frac {(d x)^{3/2} (a+b \arccos (c x))}{\sqrt {1-c^2 x^2}} \, dx}{3 d} \\ & = \frac {2 (d x)^{3/2} (a+b \arccos (c x))^2}{3 d}+\frac {8 b c (d x)^{5/2} (a+b \arccos (c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {5}{4},\frac {9}{4},c^2 x^2\right )}{15 d^2}+\frac {16 b^2 c^2 (d x)^{7/2} \, _3F_2\left (1,\frac {7}{4},\frac {7}{4};\frac {9}{4},\frac {11}{4};c^2 x^2\right )}{105 d^3} \\ \end{align*}
Time = 0.45 (sec) , antiderivative size = 202, normalized size of antiderivative = 1.85 \[ \int \sqrt {d x} (a+b \arccos (c x))^2 \, dx=\frac {1}{27} \sqrt {d x} \left (\frac {2 \left (9 a^2 c x-8 b^2 c x-12 a b \sqrt {1-c^2 x^2}+18 a b c x \arccos (c x)-12 b^2 \sqrt {1-c^2 x^2} \arccos (c x)+9 b^2 c x \arccos (c x)^2+12 a b \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {5}{4},c^2 x^2\right )+12 b^2 \sqrt {1-c^2 x^2} \arccos (c x) \operatorname {Hypergeometric2F1}\left (\frac {3}{4},1,\frac {5}{4},c^2 x^2\right )\right )}{c}+\frac {3 \sqrt {2} b^2 \pi x \, _3F_2\left (\frac {3}{4},\frac {3}{4},1;\frac {5}{4},\frac {7}{4};c^2 x^2\right )}{\operatorname {Gamma}\left (\frac {5}{4}\right ) \operatorname {Gamma}\left (\frac {7}{4}\right )}\right ) \]
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\[\int \left (a +b \arccos \left (c x \right )\right )^{2} \sqrt {d x}d x\]
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\[ \int \sqrt {d x} (a+b \arccos (c x))^2 \, dx=\int { \sqrt {d x} {\left (b \arccos \left (c x\right ) + a\right )}^{2} \,d x } \]
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\[ \int \sqrt {d x} (a+b \arccos (c x))^2 \, dx=\int \sqrt {d x} \left (a + b \operatorname {acos}{\left (c x \right )}\right )^{2}\, dx \]
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\[ \int \sqrt {d x} (a+b \arccos (c x))^2 \, dx=\int { \sqrt {d x} {\left (b \arccos \left (c x\right ) + a\right )}^{2} \,d x } \]
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Exception generated. \[ \int \sqrt {d x} (a+b \arccos (c x))^2 \, dx=\text {Exception raised: RuntimeError} \]
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Timed out. \[ \int \sqrt {d x} (a+b \arccos (c x))^2 \, dx=\int {\left (a+b\,\mathrm {acos}\left (c\,x\right )\right )}^2\,\sqrt {d\,x} \,d x \]
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